Calculus IV Quiz 2 Fall 1998 10/5/98

 
 
1. Calculate .

Integrating with respect to x gives .
Evaluating at the limits gives .
Integrating with respect to y gives .
Finally evaluating at the limits gives .
 

2. Evaluate .

The function as it stands has no elementary antiderivative with respect to x, so our only option is to reverse the order of integration.

A sketch of the region looks something like what's shown at left, extending from the right-opening parabola x = y2 on the left to y = 4 on the right, for slices from y = 0 below to y = 2 above.

To express the limits in the opposite order, we go bottom-to-top and then left-to-right. The bottom curve is y = 0, and the upper curve is . Our slices run from x = 0 to x = 4.
Thus the new integral is . Integrating with respect to y gives . Evaluating at the limits gives . This function can be integrated (using the substitution u = x2) to leave us with .